Question

Find the discriminant of (x + 1)(x - 2) + x = 0​

Answer 1

$\: \: \: \: \: \: (x + 1)(x - 2) + x = 0 \\ = > {x}^{2} + x - x = 0 \\ = > {x}^{2} = 0$

comparing it to

$a {x}^{2}+bx+c = 0$

we get a=1 ; b=0 ; c=0

SO, the discriminant is ----${b}^{2}-4ac = {0}^{2} - 4 \times 1 \times 0 = 0$

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