Find the discriminant of x2-4x+1=0
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1
D^2=b^2-2ac
= (-4)^4-4×1×1
=16-4
= 12
=√12
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Answered by
1
Answer:
In the equation
x2+4x−1=0
a = 1, b = 4, c = -1
Discriminant =
b2−4ac
=> 4²−4×1×(−1)
=> 16−4
=> 12
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