Math, asked by janhavithapar1, 1 month ago

Find the discriminant value √22+ 4x +2√2 = 0 and state the nature of the roots.

Answers

Answered by midhunmadhu1987
0

Answer:

Discriminant = 0

Nature of Roots: Real and Equal Roots

Step-by-step explanation:

Consider the general form of a quadratic equation below:

ax^{2} +bx+c=0

The discriminant of the equation is given by,

D = b^{2} -4ac

Given equation is \sqrt{2} x^{2} +4x+2\sqrt{2} =0

Here, a = \sqrt{2} , b = 4 , c = 2\sqrt{2}

So,

D = 4^{2} -4*\sqrt{2} *2\sqrt{2}

D = 16 - 16

D = 0

Since Discriminant is 0, therefore the quadratic equation has two Real and Equal roots.

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