find the discriminant value of the 5 x square - 6x + 1
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5x²-6x + 1
Discriminant= b²-4ac
= (-6)²-4(5)(1)
= 36-20
= 16
The equation has real roots.
Discriminant= b²-4ac
= (-6)²-4(5)(1)
= 36-20
= 16
The equation has real roots.
Answered by
0
5x^2 - 6x +1
=> Discriminent = b^2 - 4a*c
=> D = (-6)^2 - 4(5)(1)
=> D = 36 - 20
=> D = 16
=> Discriminent = b^2 - 4a*c
=> D = (-6)^2 - 4(5)(1)
=> D = 36 - 20
=> D = 16
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