Question

find the discriminant x square + 3 X + 1 is equal to zero​

Answer 1

Answer:

D $\neq$ 0

Step-by-step explanation:

(x^2) + 3x + 1 = 0

a = 1

b = 3

c = 1

D = $\sqrt{b^{2} - 4ac}$

D = $\sqrt{9-4(1)(1)}$ = $\sqrt{5}$

D $\neq$ 0