Question

find the discriminate of the quadratic equation
2x²-4x+3=0 & hence
write the nature of roots
​

Answer 1

Answer:

D=b²- 4ac

" = (-4)² - 4×2×3

" = -8

then

there is No real roots , so imaginary Roots

Answer 2

Given:

Quadratic Equation → 2x² - 4x + 3

To find:

Nature of roots = ?

Solution:

The general form of the Quadratic Equation is ax² + bx + c

Comparing a, b and c with the give Quadratic Polynomial;

• a = 2
• b = -4
• c = 3

Apply the formula:

   D = b² - 4ac

⇒ D = (-4)² - 4(2)(3)

⇒ D = 16 - 24

⇒ D = -8

Since the value of D is negative, the given Quadratic Equation has no real roots and only imaginary roots.

KNOW MORE:

• If the value of D was positive, then the equation would have real and unequal roots.
• If the value of D is equal to zero, then the Equation would have real and Equal roots.