Question

Find the discriminent of 2x2 + 3x + 1 = 0
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Answer 1

Step-by-step explanation:

4+3x+1=0

3x+5=0

3x=(-5)

x= -5/3

Answer 2

$\huge \fcolorbox{green}{h}{question}$

$\bf \: Find \:\: the \: discriminent \: \: of \: \: 2x \: + \: 3x \: + \: 1 \: = 0</p><p>$

$\huge \fcolorbox{gold}{t}{solution}$

$\fcolorbox{red}{t}{given = 2x(square) + 3x + 1 = 0}$

==》ON Comparing this equation with

$\tt \: a {x}^{2} + bx + c = 0 \\ \\ \bf \: where \: > a = 2. \: b = 1. \: c = 3$

$\tt \: therefore \\ \\ \tt \: {b}^{2} - 4ac = {(5)}^{2} - 4 \times 2 \times 1 \\ \\ \tt \: = 9 - 8 \\ \\ \tt \: = 1$

$\huge\tt \: x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt \: = \frac{ - 3 + \sqrt{1} }{2 \times 2} \\ \\ \bf \: x = \frac{ - 3 + 1}{4} or \: x = \: \frac{ - 3 - 1}{4} \\ \\ \bf \: x = \frac{ - 2}{4} \: or \: x = \frac{ - 4}{4} \\ \\ \tt \: x = \frac{ - 1}{2} \: or \: \\ \\ \tt \: x = - 1$

$\huge \tt \fcolorbox{aqua}{h}{be \: brainly}$

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