Question

Find the discriminent of the quadratic equation
Root 2x square+8x+2root2=0

Answer 1

Step-by-step explanation:

2x^2+8x+2√2=0

D= b^2-4ac

D=(8)^2-4(2)(2√2)

=64-16√2

=16(4-√2)

Answer 2

$Compare \: given \: Quadratic \:equation \\2x^{2}+8x+2\sqrt{2} = 0 \: with \:ax^{2}+bx+c = 0 ,\\we \:get$

$a = 2 , \: b = 8 \:and \: c = 2\sqrt{2}$

$Discreminant (D) = b^{2} - 4ac \\= 8^{2} - 4\times 2 \times 2\sqrt{2} \\= 64 - 16\sqrt{2} \\= 16(4-\sqrt{2})$

Therefore.,

$\red{ Discreminant (D) } \green {= 16(4-\sqrt{2})}$

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