Question

find the discriminent of (x_2a)(x_2b)=4ab​

Answer 1

Given :

• ( x - 2a ) ( x - 2b ) = 4ab

To Find :

• Discriminate of given equation

Solution :

( x - 2a ) ( x - 2b ) = 4ab

x² - 2bx - 2ax + 4ab = 4ab

x² - 2x ( a + b ) = 0

On comparing with ax² + bx + c = 0 , we get

• a = 1
• b = - 2 ( a + b )
• c = 0

Now , By using Discriminate formula

★ D = b² - 4ac ★

→ D = [ - 2 ( a + b ) ]² - 4 × 1 × 0

→ D = 4 ( a + b )² - 0

→ D = 4 ( a + b )² > 0

Discriminate is greater than 0 , so equation have two distinct real roots.