find the disctiminant of quadratic equation 3x^2-x-2=0
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Step-by-step explanation:
The value of discriminant of x^2 - 3x + 2
= 0 is D = b^2 - 4ac a = 1, b = - 3, c = 2 D = ( - 3)^2 - 4 × 1 × 2 = 9 - 8 = 1
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Given,
The discriminant of 3x
2
+2x+a=0 is double the discriminant of x
2
−4x+2=0
We know that the discriminant of a quadratic equation ax
2
+bx+c=0 is given by: b
2
−4ac
Hence,
(2)
2
−4×3×a=2×((−4)
2
−4×1×2)
4−12a=2×(16−8)
4−12a=16
12a=4−16
12a=−12
a=−1
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