Question

FIND THE DISPALCEMENT AND DISTANCE TRAVELLED BY A BODY IN 10S,USING THE VT GRAPH BELOW. [DIAGRAM IS THERE BUT DONT KNOW HOW TO PASTE THE DIAGRAM] PLEASE HEPL ME SOMEONE.

Answer 1

Answer:

Let 0s to 1s the area is A

1

, 1s to 2s the area is A

2

, 2s to 3s the area is A

3

, 3s to 4s the area is A

4

, 4s to 5s the area is A

5

.

Since, the displacement is equal to the area enclosed in velocity time graph where area below time axis is negative.

The displacement is given as,

d=A

1

+A

2

+A

3

+A

4

−A

5

d=(1×1)+(

2

1

×1×1)+(

2

1

×1×1)+(1×1)−(1×1)

=2m