Question

Find the displacement and acceleration from time 0-2 sec, 2-10 sec, 10-12 sec, and
12-16 seconds. Also tell the type of motion in al the regions. Find the total
displacement​

Answer 1

Answer:

The answer is -

Explanation:

To find the displacement and the acceleration of the object in different time intervals, if 0-2 seconds, 2-10 seconds, 10-12 seconds and 12-16 seconds.

Follow the formulas of the physical quantity and observe the graph

According to the graph,

The velocity of the object in 0-2 seconds is 8 m/s

So,

As we know that velocity = displacement/time taken

                                       8 = displacement/2

                                 8 X 2 = displacement

                   displacement = 16 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

                                                  = 2 - 0/2

                                                  = 2/2

                                                  = 1 m/$s^{2}$

Now,

According to the graph,

The velocity of the object in 2-10 seconds is also 8 m/s

So,

As we know that velocity = displacement/time taken

                                      8  = displacement/10 - 2

                                      8  = displacement/8

                                8 X 8 = displacement    

                   displacement = 64 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

                                                  = 10 - 2/8

                                                  = 8/8

                                                  = 1 m/$s^{2}$

Now,

According to the graph,

The velocity of the object in 10-12 seconds is 4 m/s

So,

As we know that velocity = displacement/time taken

                                       4 = displacement/12 - 10

                                       4 = displacement/2

                                4 X 2 = displacement

                   displacement = 8 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

                                                  = 12 - 10/2

                                                  = 2/2

                                                  = 1 m/$s^{2}$

Now,

According to the graph,

The velocity of the object in 12-16 seconds is 4 m/s

So,

As we know that velocity = displacement/time taken

                                       4 = displacement/16 - 12

                                       8 = displacement/4

                                8 X 4 = displacement

                   displacement = 32 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

                                                  = 16 - 12/4

                                                  = 4/4

                                                  = 1 m/$s^{2}$

Total displacement = (16 + 64 + 8 + 32)m

                                = (80 + 40)m

                                 = 120 meters

Answer 2

Answer:

here is your answer

Explanation:

To find the displacement and the acceleration of the object in different time intervals, if 0-2 seconds, 2-10 seconds, 10-12 seconds and 12-16 seconds.

Follow the formulas of the physical quantity and observe the graph

According to the graph,

The velocity of the object in 0-2 seconds is 8 m/s

So,

As we know that velocity = displacement/time taken

8 = displacement/2

8 X 2 = displacement

displacement = 16 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

= 2 - 0/2

= 2/2

= 1 m/s^{2}s

2

Now,

According to the graph,

The velocity of the object in 2-10 seconds is also 8 m/s

So,

As we know that velocity = displacement/time taken

8 = displacement/10 - 2

8 = displacement/8

8 X 8 = displacement

displacement = 64 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

= 10 - 2/8

= 8/8

= 1 m/s^{2}s

2

Now,

According to the graph,

The velocity of the object in 10-12 seconds is 4 m/s

So,

As we know that velocity = displacement/time taken

4 = displacement/12 - 10

4 = displacement/2

4 X 2 = displacement

displacement = 8 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

= 12 - 10/2

= 2/2

= 1 m/s^{2}s

2

Now,

According to the graph,

The velocity of the object in 12-16 seconds is 4 m/s

So,

As we know that velocity = displacement/time taken

4 = displacement/16 - 12

8 = displacement/4

8 X 4 = displacement

displacement = 32 m

And,

As we know that acceleration = final velocity - initial velocity/time taken

= 16 - 12/4

= 4/4

= 1 m/s^{2}s

2

Total displacement = (16 + 64 + 8 + 32)m

= (80 + 40)m

= 120 meters