Question

Find the displacement at end of 30 second, 90 second, and 80 second.​

Answer 1

Answer:

S(30)= u×30+1/2×a×30^2

S(90)=u×90+1/2×a×90^2

S(80)=u×80+1/2×a×80^2

Explanation:

S=ut+1/2at^2

S- displacement

u- initial velocity

a- acceleration

t- time