find the displacement at first 20 seconds. Graph shows rectilinear motion. With detailed explanation
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TO FIND THE DISPLACEMENT IT IS REQUIRED TO FIND THE AREA OF THE GRAPH AT THE PARTICULAR TIME .
Area = [(50*20)-(50*10)/2]
=1000-250
area =750 m^2
This implies the displacement : 750mts at 20 secs .
thnx ma for spndng ur REASONABLE TIME wth my ans.
gouthamchowdary:
please answer my another question
what kindda explanation do you need
ntg solution in detail
a body starts from rest and moves with a uniform acceleration then the ratio of distance covered by it during 5th second of its motion to the distance travelled in 5 second of motion
i didnt get any such qns
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