Question

Find the displacement of a particle after 10 seconds starting from rest with a uniform acceleration of 2m/§

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt \therefore Displacement \: after \: 10 \: sec \: is \: 100 \: m}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Time(t) = 10 \: sec \\ \\ \tt: \implies Acceleration(a) = 2 { \: m/s}^{2} \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Displacement(s) =?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \tt: \implies s =0 \times 10 + \frac{1}{2} \times 2 \times {10}^{2} \\ \\ \tt: \implies s =0 + {10}^{2} \\ \\ \green{\tt: \implies s =100 \: m} \\ \\ \green{\tt \therefore Displacement \: after \: 10 \: sec \: is \: 100 \: m}$

Answer 2

Given ,

Time (t) = 10 sec

Initial velocity (u) = 0 m/s

Acceleration (a) = 2 m/s²

We know that ,

The Newton's second equation of motion is given by

$\boxed{ \sf{S = ut + \frac{1}{2} a {(t)}^{2} }}$

Thus ,

S = 0(10) + 1/2 × 2 × (10)²

S = (10)²

S = 100 m

$\sf \therefore \underline{The \: displacement \: of \: particle \: is \: 100 \: m}$