Question

find the displacement of the particale when it's velocity becomes 10 mitar per second if acceleration is 5 mitar per second sqare all through ?​

Answer 1

Answer:

The distance travelled in 4 seconds is 40 m.

The distance travelled in 5 seconds is 62.5m.

The distance travelled in 5th second is 22.5 m.

Explanation:  

Given:  

Initial velocity (u) = 0  

Acceleration (a) = 5 m/s²  

The distance travelled by the particle in t = 4 s  

Let the distance travelled in 4 seconds by the particle be ''  

So,  

By using the equation of motion,  

= ut +  

= 40 m

Therefore, the distance travelled in 4 seconds by the particle is 40 m.

The distance travelled by the particle in t = 4 s

Let the distance travelled in 4 seconds by the particle be ''

So,

By using the equation of motion,

= ut +  

= 62.5 m

Therefore, the distance travelled in 5 seconds by the particle is 62.5 m.

The distance travelled in 5th second by the particle = the distance travelled in 5 seconds - the distance travelled in 4 seconds  =  

= 62.5 m - 40 m

= 22.5 m

Therefore, the distance travelled in 5th second by the particle is 22.5 m

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