find the distance and displacement of an object moving around a circular track of diameter 5 and completes one and half round
Answers
Explanation:
displacement is the shortest distance travelled=5 cm(diameter)
total distance travelled= 1st round + half round
2pieR + pie R
pie R (2+1)
22/7 × 5/2 (3)
11/7 ×5×3
11×15/7
165/7
Consider the figure attached also.
The figure shows a circular track of diameter AB = 5.
Here the object starts moving from A.
If the object completes one and a half round, then probably the object finishes its movement at B.
Here the distance traveled by the object is 3/2 times the perimeter of the circular track.
We know perimeter of a circle of radius r is 2πr. So,
Distance = 2πr × 3/2 = 3πr.
Since the diameter of the circular track is 5, its radius is OA = OB = 5/2. So,
Distance = 3π · 5/2 = 15π/2.
Here we can take the value of π as 22/7. So,
Distance ≈ (15 · 22/7) / 2 = 165 / 7 ≈ 23.57
Hence we got the distance.
If the object starts moving from A and ends at B, then the displacement will be AB = 5.
Hence we got the displacement.
