Question

find the distance and speed with displacement.
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Answer 1

Explanation:

D= length of the semicircle OA'A+ length

AB+ length BC. This D=πR+R+2R=(π+3)R.

Since OA=2R, AB=R, and BC=2R, the

coordinates of C can be given as C≡(2R.R2R). Then the position of C is expressed as:

r→=2Rjˆ+2Rjatk

As  v→(=O→C)=r→c−r→0, Substituting r→c and r→0=0iˆ+0jˆ+0kˆ,

we obtain s→=(2iˆ+jˆ+2kˆ)R.

Its magnitude ∣∣s→∣∣=(22+12+22−−−−−−−−−−√)R=3R

Hence, Ds=(π+3)R3R=π+33.