Question

Find the distance at which the chord lies from the centre of a circle if radius=10 cm and length of chord =12 cm.

Answer 1

Answer:

phythagorus theorem se hoga

Step-by-step explanation:

12ka 6ho jayaga or fir hypoteniussequare =perpwndicularseqplus baseseq 6ka 36and 12ka 144than 144-36( )than uska square root answer aaagya

Answer 2

Answer:

Distance of chord from the centre = 8cm

Step-by-step explanation:

Theorem used: Perpendicular from the centre bisects the chord.

Given:

1. Radius = 10cm
2. Length of chord = 12cm

To find:

Distance of chord from the centre

Procedure:

Construct a perpendicular OD from the centre to the chord AB. We know that a perpendicular from the centre bisects the chord. Therefore, AD=BD=6cm.

In Triangle OBD,

$OD^{2} = OB^{2}-BD^{2}$

OD = $\sqrt{10^{2} - 6^{2}$

OD = $\sqrt100-\sqrt 36 = \sqrt64$ = 8cm..

FIGURE IS ATTACHED.