find the distance between 0,0 sin 30,cos 30
Answers
Given : Point (0 , 0) and (sin 30° , Cos 30°)
To Find : Distance between points
Solution:
Point (0 , 0) and (sin 30° , Cos 30°)
Distance between points
= √( (Sin 30° - 0)² + (cos 30° - 0)² )
= √( (Sin 30°)² + (cos 30°)² )
= √( Sin ²30° + cos ²30° )
sin²x + cos²x = 1
= √1
= 1
Distance between points (0 , 0) and (sin 30° , Cos 30°) is 1
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Given :- find the distance between (0,0) and (sin 30°,cos 30°) .
Answer :-
we know that, using distance formula, distance between two coordinates (x1,y1) and (x2,y2) is given by,
- √{(x2 - x1)² + (y2 - y1)²} .
so, putting given values we get,
→ D = √{(sin30° - 0)² + (cos30° - 0)²}
→ D = √(sin 30°)² + (cos 30°)²
→ D = √{(1/2)² + (√3/2)²
→ D = √(1/4 + 3/4)
→ D = √(4/4)
→ D = 1 unit (Ans.)
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