find the distance between 0,5by7
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Answer:
P≡(−5,7)
Q≡(−1,3)
∴d(P,Q)=
(−5−(−1))
2
+(7−3)
2
∴d(P,Q)=
16+16
∴d(P,Q)=
32
∴d(P,Q)=4
2
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