Question

find the distance between (0,- sin x)and (-cosx,0)​

Answer 1

the distance between (0,- sin x)and (-cosx,0) = 1

Step-by-step explanation:

the distance between (0,- sin x)and (-cosx,0)

$= \sqrt{( (- \cos(x) - 0)^{2} + (0 - ( - \sin(x))^{2} }$

$= \sqrt{ \cos^{2} (x) +\sin^{2} (x) } \\ = \sqrt{1} \\ = 1$

the distance between (0,- sin x)and (-cosx,0) = 1

learn more:

 the distance between the points:(3,-2) and (15,3) - Brainly.in

https://brainly.in/question/12432245

Find value of P , if the distance between the points are ( 4 , p ) and ...

https://brainly.in/question/7650873

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The distance is 1 unit.}}}$

Step-by-step explanation:

We have the following distance formula :

Distance formula :  The distance between the points (a, b) and (c,d) is given by

$D=\sqrt{(c-a)^2+(d-b)^2}.$

We will also use the following trigonometric formula :

$\cos^2\theta+\sin^2\theta=1.$

The distance between the points (0, -sin x)and (-cos x, 0)​ is given by

$D\\\\=\sqrt{(-\cos x-0)^2+(0+\sin x)^2}\\\\=\sqrt{\cos^2x+\sin^2x}\\\\=\sqrt1\\\\=1.$

Thus, the required distance between the given points is 1 unit.

Learn more#

Question : Find the distance between the points ( -6, -1) and (- 6, 11).

Link : https://brainly.in/question/1567591.