Question

find the distance between (-1,4) and (6,-7)​

Answer 1

Answer:

d=√170

d= 13.04 units

Explanation:

To find the distance between points at

(1,4) and(−6,−7)

we can use the distance formula

d=√(y2−y1)2+(x2−x1)2

for the points given x1=1

y1=4

x2=−6

y2=−7

plugging in the values we get

d=√(−7−4)2+(−6−1)2

simplifying the parenthesis

d=√(−11)2+(−7)2

Simplifying the squares

d=√121+49

simplifying the radical

d=√170

d= 13.04 units

Answer 2

Answer:

$D=$ √170

$D= 13.04 units$

Step-by-step explanation:

To find the distance between points at  (-1,4) and (6,-7)

We can use distance formula

$D=\sqrt{(y2-y1)^{2}+(x_{2}-x_{1})^{2} }$

for the points given  

$x_{1 } =-1\\y_{1} =4\\\\x_{2} =6\\y_{2} =-7$

plugging in the values we get

$D=\sqrt{(-7-4)^2+(-6-1) ^2$

simplifying the parenthesis

$D=\sqrt{(-11)^2+(-7)^2}$

Simplifying the squares

$D=\sqrt{121+49}$

simplifying the radical

$D\sqrt{170}$

$D= 13.04 units$

Hope it helps

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