find the distance between (2,3),(4,1) by distance formulA
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2
√(4-2)²+(1-2)²=√(2)²+(-1)²=√4-1=√3
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8
x₁=2,x₂=4 ,y₁=3,y₂=1
xy=√[x₂-x₁]²+[y₂-y₁]²
√[4-2]²+[1-3]²
⇒√2²+(-2)²
⇒√4+4
⇒√16
⇒4 sq units.
xy=√[x₂-x₁]²+[y₂-y₁]²
√[4-2]²+[1-3]²
⇒√2²+(-2)²
⇒√4+4
⇒√16
⇒4 sq units.
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