find the distance between (2,3,5)and (4,3,1)
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Answered by
8
√(2-4)^2 + (3-3)^2 + (5-1)^2
√(-2)^2 + 0 + (4)^2
√4 + 16
√20 units
√(-2)^2 + 0 + (4)^2
√4 + 16
√20 units
Answered by
6
distance formula in 3D = under root of {(x2-x1)^2+(y2-y1)^2+(z2-z1)^2}
let x1=2, y1=3, z1=5
x2=4, y2=3, z2=1
distance, D= {(4-2)^2+(3-3)^2+(1-5)^2}
D=4+0+16
D=20
let x1=2, y1=3, z1=5
x2=4, y2=3, z2=1
distance, D= {(4-2)^2+(3-3)^2+(1-5)^2}
D=4+0+16
D=20
ak4717:
heybrother!you are wrong
yes i have forgotten the square root :P
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