Question

find the distance between (2, -3) and (10, y) is 10 units find the value of y​

Answer 1

Step-by-step explanation:

$using \: distance \: formula : \\ \sqrt{ {(x_2-x_1)}^{2}+ {(y_2-y_1)}^{2} } \\ according \: to \: the \: question : \\ \sqrt{ {(10-2)}^{2}+ {(y-( - 3))}^{2} } = 10 \\ square \: on \: both \: sides : \\ {(10-2)}^{2}+ {(y-( - 3))}^{2} = 100\\ {(8)}^{2}+ {(y + 3)}^{2} = 100 \\ 64 + {y}^{2} + 6y + 9 = 100 \\ {y }^{2} + 6y + 73 = 100 \\ {y}^{2} + 6y - 27 = 0 \\ {y}^{2} + 9y - 3y - 27 = 0 \\ y(y + 9) - 3(y + 9) \\ (y - 3)(y + 9) \\ y = 3 \: , \: - 9</p><p>$

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