Question

find the distance between (-2,-3) and(3,2)​

Answer 1

Step-by-step explanation:

answer is given here

Answer 2

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Given:-

• Two points (-2,-3) and (3,2)
• x1= -2, x2= 3
• y1= -3 , y2= 2

Let A= (-2,-3)

and B=(3,2)

Now, we can see that Point A lies in 3rd quadrant and Point B lies in 1st quadrant

To Find:-

• Distance Between A And B

Information:-

To Find the distance between 2 points A(x1,y1) and B(x2,y2)

We Use Distance Formula:-

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

Solution:-

Substituting the values in the Equation of distance

$= > d = \sqrt{ ({3 - ( - 2))}^{2} + {(2 - ( - 3))}^{2} }$

$= > d = \sqrt{ {5}^{2} + {5}^{2} }$

$= > d = \sqrt{25 + 25}$

$= > d = \sqrt{50}$

$= > d = \sqrt{5 \times 5 \times 2}$

$= > d = 5 \sqrt{2} units$