Question

find the distance between (2-5)and (-2,3).

Answer 1

The distance between 2,-5 is 6 and in -2,3 is 4

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• The distance between the points = 4√5 units

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$\sf{\underline{\green{Given:-}}}$

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• The given points are (2,-5) and (-2,3).

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$\sf{\underline{\green{Find:-}}}$

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• The distance between the points = ?

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$\sf{\underline{\green{Explanation:-}}}$

$\sf{\underline\purple{Formula\:Used\:Here:-}}$

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$\bigstar\boxed{\sf{\red{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}}}$

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$\sf{\underline{\pink{Putting\:the\:values:-}}}$

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$\dashrightarrow \sf {Distance = \sqrt{(-2 -2)^2 + (3 - (-5))^2}}$

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$\dashrightarrow \sf {Distance = \sqrt{(-4)^2 + (3+5)^2} }$

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$\dashrightarrow \sf {Distance = \sqrt{16 + 64} }$

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$\dashrightarrow \sf {Distance = \sqrt{80} }$

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$\dashrightarrow \sf {Distance = \sqrt{16 \times 5} }$

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$\dashrightarrow{\gray{ \underbrace{\boxed{\underline{\underline{\blue{ \tt Distance = 4\sqrt{5}\: units }}}}}}}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• The distance between the points is 4√5 units

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$\rule{200}{2}$