find the distance between -3, 0 and the line 2 x minus 3 Y + 8 is equal to zero
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2x-3y+8=0
2x-3y=-8
*let x be 2 and y be 4
2(2)-3(4)
4-12=-8
-8=-8
LHS=RHS
= (2,4)
and then find the distance between (-3,0) and (2,4)
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determine the equation of the line the portion of which intercepted by the axes is divided by the point (4,1) in the ratio of 1:2
plz answer this one
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