Question

Find the distance between 3x-4y+5=0 and 6x-8y+2=0

Answer 1

Answer:

3x- 4y=-5

3x= -5+4y

x = -5+4y÷3

Let's put the value of x in the eq. 2

6(-5+4y÷3) -8y+2=0

-10+8y-8y+2=0

-10+y+2=0

-8+y=0

y=8

Now,

putting the value of y we get

x=-5+4y÷3

x=-5+4×8÷3

x=27÷3

x=9

So, the distance between the two equation

=(3×9-4×8+5) - (6×9-8×8+2)

=0-(-8)

=8

Step-by-step explanation:

First find the unknown value of x and y by substitution method and then put their values on their equation and lastly subtract the two equation