Question

Find the distance between ( 4 , -3) from origin. justify ? tell in stepwise​

Answer 1

Answer:

The distance between (4,-3) and origin i.e., (0,0) is 5.

Step-by-step explanation:

The formula used for calculationg distance between two points (x,y) and (a,b) is

Let s be the distance, $s=\sqrt{(x-a)^{2}+(y-b)^{2} }$

Here (x,y)=(4,-3)

(a,b)=(0,0)

Using the formula above we get s as,

$s=\sqrt{(4-0)^{2} +(-3-0)^{2} } \\s=\sqrt{4^{2}+(-3)^{2} } \\s=\sqrt{16+9} \\s=\sqrt{25} \\s=5$

Thus, the distance of point (4,-3) from origin is 5.

Answer 2

Given data in the question is distance  (4,-3)

We have to find distance between $(4,-3)$ from origin.

Distance can be written as A$(x_{1} ,y_{1} )$ be the distance between the two points.

another distance can be written as B$(x_{2} ,y_{2} )$ be also distance between two points.

By using distance formula=$\sqrt{(x_{1-x_{2} } )^{2}+(y_{1} -y_{2} )^{2} } }$

Putting the values of A$(0,0)$ and B$(4,-3)$,we get

Distance =$\sqrt{(4-0)^{2}+(0-3)^{2} }$

taking square of $4$ and $3$, we get

Distance =$\sqrt{4^{2} +3^{2} }$

$4^{2} is 16$ and $3^{2} is 9$ ,adding both the square and taking square root, we get

by adding$16$  and $9$ we get ,$\sqrt{16+9} =\sqrt{25}$=$5$ units

Therefore, the distance between $(4,-3)$ from origine is 5 units.