find the distance between :
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ƓƖƔЄƝ:-
- p( sin∅ ,cos ∅) and Q(-sin∅ , - cos ∅)
ƬƠ ƑƖƝƊ:-
- distance between P and Q
ƧƠԼƲƬƖƠƝ:-
using distance formula ,
➔√(x2-x1)²+(y2-y1)²
put value ,
➔√(-sin∅ -sin∅)² + (-cos∅-cos∅)²
➔√ (-2sin∅)²+(-2cos∅)²
➔√ 4 sin²∅ + 4 cos ²∅
➔ √ 4 (sin²∅ + cos ²∅)
as ,we know sin²∅ + cos²∅ = 1
➔ √ 4
➔√ 2×2
➔ 2
hence ,the distance between point P and Q is 2
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