Question

find the distance between (7,1) and (3,5) ​

Answer 1

Answer: The distance is 5.6568 units

Step-by-step explanation:

Use distance formula

$d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}$

Here , x1 = 7 and y1= 1

          x2= 3 and y2 = 5

therefore,

$d = \sqrt{(3-7)^{2}+(5-1)^{2}$

= 5.6568 uts.