Question

* Find the distance between A(−1,2) and B(4,2)?​

Answer 1

Answer:

Input Data :

Point 1(xA,yA)(xA,yA) = (4, 3)

Point 2(xB,yB)(xB,yB) = (3, -2)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2

= √(−1)2+(−5)2(-1)2+(-5)2

= √1+251+25

= √2626 = 5.099

Distance between points (4, 3) and (3, -2) is 5.099