Question

find the distance between (a cos teeta ,0) and ( 0, sin teeta )​

Answer 1

Step-by-step explanation:

distance is 1

remaining is in picture

Answer 2

$\huge\star\:\:{\orange{\underline{\purple{\mathcal{Solution:-}}}}}$

The distance between (a cos theta,0) and (0 , a sin theta) is

$= \sqrt{( {0 - a \cos(theta)) }^{2} } + ( {a \sin(theta - 0) })^{2}$

$\sqrt{ {( - a \cos(theta) ) }^{2} + {(a \sin(theta) )}^{2} }$

$\sqrt{ {a}^{2} { \cos }^{2} theta + {a}^{2} { \sin }^{2} theta}$

$= \sqrt{ {a}^{2} ({ \cos }^{2}theta + { \sin }^{2} theta) }$

$= \sqrt{ {a}^{2} 1}$

$= \sqrt{ {a}^{2} }$

$\boxed {= a units}$