Find the distance between (a cos theta,0)and (0,a sin theta)
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Let theta is x.
Distance = [(a cosx - 0 )² + ( 0 - a sinx)²]½
= ( a² cos²x + a² sin²x )½
=[a²(cos²x +sin²x )]½
= ( a² )½
=a
Distance = [(a cosx - 0 )² + ( 0 - a sinx)²]½
= ( a² cos²x + a² sin²x )½
=[a²(cos²x +sin²x )]½
= ( a² )½
=a
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