Question

find the distance between ( cos A - sin A) ( sin A , cos A)​

Answer 1

Answer:

Distance=√2

Step-by-step explanation:

given,

A=(cosA,-sinA)

B=(sinA,cosA)

Distance between two points is positive Square Root of sum of Square of difference of ordinates and absiccas .

So distance between two points D = √{ (sinθ - cos θ)² +(cos θ+ sinθ)²}

D = √[ (sinθ )² + (cos θ)² - 2 sin θ cosθ +(cos θ )² + ( sin θ) ² +2 cos θ sinθ) ]

Since (sinθ )² + (cos θ)² = 1

Therefore

D= √[ ( 1 - 2 sin θ cosθ + 1 +2 cos θ sinθ) ]

Cancelling 2 sin θ cos θ and -2 cos θ sinθ)

D = √2

Hope you understand

Please make it a brainlist answer