Question

find the distance between L (2,3) & M (-1,5)​

Answer 1

Answer:

$\sqrt{13}$

Step-by-step explanation:

d=√(x2-x1)²+(y2-y1)²

L(x1,y1) = (2,3)

M(x2,y2) = (-1,5)

d=√(-1-2)²+(5-3)²

 =√(-3)²+(2)²

 =√9+4

 =√13

Answer 2

Answer:

distance L, m = √-1

Step-by-step explanation:

$d(lm) = \sqrt{(x2 - x1) + (y2 - y1)}$

therefore,

$d(lm) = \sqrt{ ( - 1 - 2) + (5 - 3)}$

$d(lm) = \sqrt{ - 3 + 2}$

$d(lm) = \sqrt{ - 1}$