Question

find the distance between line x+y+2=0 and point (1,1)​

Answer 1

3 units

the another point is (-2,-2)

As x+y+2=0 then x+y=-2

if x =0 then y=-2 and if y=0 then x=-2

now point here is (-2,-2)

therefore the points are (1,1) and (-2,-2) and distance between them is 3 unit.