Question

Find the distance between lines 4x+3y=11 and 4x+3y=15/2

Answer 1

Step-by-step explanation:

4x+3y=11

x=11/4

y=11/3

4x+3y=15/2

x=15/2

y=5/2

root(11/4-15/2)²+(11/3-5/2)²

solve this u get urs answer perfectly

Answer 2

Answer:

Step-by-step explanation:

4x+3y=11

4x=11-3y

x=11-3y/4....................(1)

4x+3y=15/2..................(2)

Now,

Putting value of con equations (2)

We get

4(11-3y/4)+3y=15/2

11-3y+3y=15/2

11=15/2

I think question is wrong

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