Question

Find the distance between mid-point of line segment AB with A(2,-7),B(9,-2) and the point C(5,-6)

Answer 1

Answer:

√2.5

Step-by-step explanation:

Mid point is average of coordinates

Mid pt = (2+9)/2 = 5.5

= (-7-2)/2 = -4.5

So mid pt = 5.5,-4.5

Distance = √{(x1-x2)^2 + (y1-y2)^2}

= √(0.25+2.25)

= √2.5

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