Question

find the distance between ogive
and. 8, 6​

Answer 1

Answer:

$d=10u$

Step-by-step explanation:

I will assume you are asking the distance from the center of the CARTESIAN PLANE (0,0) and the coordenate (8,6).

First it is important to understand that when we use the cartesian coordenates, this means we have a value for the x axis and a value for the y axis.

That is to say that (8,6) means x=8, and y=6.

If we graph this coordinate on the cartesian plane, we can see that the distance between this coordinate and the center is a straight line between this two points.

We can build a straight triangle if we project the distances of both axis, this means we will have a triangle with two known legs (8u and 6u) and an unknown hypotenuse.

At last, we use the PITHAGORAS THEOREM to find the hypotenuse, which is the distance between (0,0) and (8,6).

$d=\sqrt{8^{2}+6^{2} }\\d=\sqrt{64+36}\\d=\sqrt{100}\\d=10u$

Answer 2

question is to find distance between origin and given point (8,6)

it is very well known that origin point is (0,0)

Distance between two point (x1 , y1) & (x2, y2) is calculated as below

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

here x2 = 8 y2 = 6

x1 = 0 & y1 = 0

x2 -x1 = 8 -0 = 8

y2 -y1 = 6 -0 = 6

so

$distace \: = \sqrt{ {8}^{2} + {6}^{2} } \\ \implies \: distance \: = \sqrt{64 + 36} \\ \implies \: distance \: = \sqrt{100} \\ \implies \: distance \: = 10 \: units$

answer is 10 units