find the distance between p(2,-2) and q(-1,2)
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the distance is
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0
Distance between two points (x1,y1) ,(x2,y2)
=√(x2-x1)^2 + (y2-y1)^2
Here ,
√(-1-2)^2 + (2+2)^2
=√(-3)^2 + (4)^2
=√9+16
=√25
=5
=√(x2-x1)^2 + (y2-y1)^2
Here ,
√(-1-2)^2 + (2+2)^2
=√(-3)^2 + (4)^2
=√9+16
=√25
=5
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