find the distance between P(2,2) and Q(5,6)
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Answer:
The distance between P(2,2) and Q(5,6) is 5 units.
Step-by-step explanation:
Given,
P(2,2) and Q(5,6)
x1 = 2 ,x2 = 5; y1 = 2, y2 = 6,
Now,
By using distance formula,
W.K.T,
___________________________________
The distance between 2 points = √(x2-x1)^2 + (y2-y1)^2
___________________________________
= √(5-2)^2 + (6-2)^2
= √(3)^2 + (4)^2
= √(9) + (16)
= √25
= √5×5
= 5 units
:. PQ = 5 units.
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