Question

find the distance between p(-3,4) and Q (1,-2)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\sf\huge \mathbb{\underline{\underline{{Solution}}}}$

Here ,the two point is given and we have to find the distance between these points.For this we use distance formula for finding the distance.

Distance formula

Distance formulaD=√(x₂- x₁)²+(y₂- y₁)²

Distance between P and Q

P (-3,4) & Q( 1,-2)

x₁=-3;x₂ = 1 ; y₁= 4 & y₂ = -2

By using distance formula :

Distance between the point P&Q

PQ=> √ (x₂- x₁)²+(y₂- y₁)²

PQ=>√((1-(-3))²+(-2-4)²

PQ=>√(1+3)²+(-6)²

PQ=>√4²+(-6)²

PQ=>√ 16+36

PQ=>√52

PQ=2√13

Hence,the distance between P(-3,4)& Q(1,-2) is 2√13 units .

More information=>

• Distance formula are used to find the distance between any two given points in XY plane only of the coordinates are known.