find the distance between P(√a,√b) and Q(-√a,-√b)
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Answer:
Step-by-step explanation:
Given that,
P ( x1, y1) = ( √a, √b ) and Q (x2, y2) = ( - √a , - √b )
By using distance formula,
d = √ ( x2 - x1 )² + ( y2 - y1 )²
= √ ( - √a - √a )² + ( - √b - √b )²
= √( - 2√a )² + ( - 2√b )²
= √ 4a + 4b
= √4 ( a + b )
= 2√(a + b) units is the answer.
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