Find the distance between P(x, y) and Q (x, y,) when : (i) PQ is parallel to the -axis, (ii) PQ is parallel to the x-axis.
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Answer:
Equation of line with slope m passing through point (4,−5) is given by,
y+5=m(x−4)⇒mx−y−4m−5=0
Given distance of above line from the point (−2,3) is 12
⇒
∣
∣
∣
∣
∣
m
2
+1
m(−2)−3−4m−5
∣
∣
∣
∣
∣
=12
⇒
∣
∣
∣
∣
∣
m
2
+1
3m+4
∣
∣
∣
∣
∣
=6
⇒(3m+4)
2
=36(m
2
+1), square both sides
⇒27m
2
−24m+20=0
Discriminant of of above quadratic is, (−24)
2
−4⋅27⋅20=−1584<0
Hence, there no real root of above quadratic.
i.e. there does not exist any line at a distance 12 from the point (−2,3)
and passing through the point (4,−5)
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