Math, asked by gowrir20, 5 months ago


Find the distance between P(x, y) and Q(x, y) when :( PQ is parallel to the
v-atis. (ii) PQ is parallel to the x-axis.

Answers

Answered by rohitkhajuria90
3

Distance between two points =

 \sqrt{ {(x_2-x_1)}^{2}  +  { (y_2-y_1)}^{2} }

(i) when PQ is parallel to y-axis, which means that the value of x will remain same hence,

 PQ = \sqrt{ {(x_2-x_1)}^{2}  +  { (y_2-y_1)}^{2} } \\ where \: x_2 = x_1 \\ PQ = \sqrt{ {(x_2-x_2)}^{2}  +  { (y_2-y_1)}^{2} }  \\ PQ = \sqrt{   { (y_2-y_1)}^{2} } \\  PQ =     (y_2-y_1)

(ii) when PQ is parallel to x-axis, which means that the value of y will remain same

PQ = \sqrt{ {(x_2-x_1)}^{2}  +  { (y_2-y_1)}^{2} } \\ where \: y_2 = y_1 \\ PQ = \sqrt{ {(x_2-x_1)}^{2}  +  { (y_2-y_2)}^{2} } \\ PQ = \sqrt{ {(x_2-x_1)}^{2} } \\ PQ = (x_2-x_1)

Answered by Anonymous
2

Answer:

i) modulus of y2 - y1

ii) modulus of x2 - x1

Step-by-step explanation:

i)

PQ is parallel to y-axis--> the x coordinate of both points is same. Hence the distance formula:

root over (y2-y1) whole squared, that is

| y2 - y1 | -- ( | | is modulus)

ii)

PQ is parallel to x- axis, then their y coordinate will be same. Hence the distance formula:

root over (x2-x1) whole squared, that is

| x2 - x1 | -- ( | | is modulus)

Hope that you will find this useful :)

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