Question

Find the distance between parallel lines 5x+4y-3=0 and 5x+4y+5=0

Answer 1

Answer:

8/√41

Step-by-step explanation:

from given equations

a=5

b=4

c=-3

d=5

distance =(d-c) /√(a^2+b^2)

= ( 5+3)/√(25+16)

=8/√41