Find the distance between parallel lines 5x+4y-3=0 and 5x+4y+5=0
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Answer:
8/√41
Step-by-step explanation:
from given equations
a=5
b=4
c=-3
d=5
distance =(d-c) /√(a^2+b^2)
= ( 5+3)/√(25+16)
=8/√41
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