Question

find the distance between parallel lines 9x+6y-7=0 and 3x+2y+6=0


Plz help me with correct and complete explanation for the question ​

Answer 1

Answer:

Distance = $\sqrt{13)$ units

Step-by-step explanation:

line 1 : 9x+6y-7=0

line 2 : 3x+2y+6=0

Here, c₁ = -7 , c₂ = 6

Distance between 2 parallel lines = mod[ (c₁ - c₂) / rt of (a²+b²) ]

  Hence we got,

     Distance = $\sqrt{13)$ units